本文实例讲述了php正则验证email的方法。分享给大家供大家参考。具体如下:
<?php
function validateemail($email)
{
$isvalid = true;
$atindex = strrpos($email, "@");
if (is_bool($atindex) && !$atindex)
{
$isvalid = false;
}
else
{
$domain = substr($email, $atindex+1);
$local = substr($email, 0, $atindex);
$locallen = strlen($local);
$domainlen = strlen($domain);
if ($locallen < 1 || $locallen > 64)
{
// local part length exceeded
$isvalid = false;
}
else if ($domainlen < 1 || $domainlen > 255)
{
// domain part length exceeded
$isvalid = false;
}
else if ($local[0] == '.' || $local[$locallen-1] == '.')
{
// local part starts or ends with '.'
$isvalid = false;
}
else if (preg_match('/\.\./', $local))
{
// local part has two consecutive dots
$isvalid = false;
}
else if (!preg_match('/^[a-za-z0-9\-\.]+$/', $domain))
{
// character not valid in domain part
$isvalid = false;
}
else if (preg_match('/\.\./', $domain))
{
// domain part has two consecutive dots
$isvalid = false;
}
else if(!preg_match('/^(\\.|[a-za-z0-9!#%&`_=\/$'*+?^{}|~.-])+$/', str_replace("\\","",$local)))
{
// character not valid in local part unless
// local part is quoted
if (!preg_match('/^"(\\"|[^"])+"$/', str_replace("\\","",$local)))
{
$isvalid = false;
}
}
if ($isvalid && !(checkdnsrr($domain,"mx") || checkdnsrr($domain,"a")))
{
// domain not found in dns
$isvalid = false;
}
}
return $isvalid;
}
?>
ps:这里再为大家提供2款非常方便的正则表达式工具供大家参考使用:
javascript正则表达式在线测试工具:
http://tools.jb51.net/regex/javascript
正则表达式在线生成工具:
http://tools.jb51.net/regex/create_reg
希望本文所述对大家的php程序设计有所帮助。
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